| Voorbeeld 1 | Voorbeeld 2 |
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$ \eqalign{ & 4\log (2x + 2) = - 2 \cr & \log (2x + 2) = - \frac{1} {2} \cr & 2x + 2 = 10^{ - \frac{1} {2}} \cr & 2x + 2 = \frac{1} {{10^{\frac{1} {2}} }} \cr & 2x + 2 = \frac{1} {{\sqrt {10} }} \cr & 2x = \frac{1} {{\sqrt {10} }} - 2 \cr & x = \frac{1} {{2\sqrt {10} }} - 1 \cr & x = \frac{{\sqrt {10} }} {{20}} - 1 \cr} $ |
$ \eqalign{ & ^4 \log (2x + 2) = - 2 \cr & 2x + 2 = 4^{ - 2} \cr & 2x + 2 = \frac{1} {{4^2 }} \cr & 2x + 2 = \frac{1} {{16}} \cr & 2x = - 1\frac{{15}} {{16}} \cr & x = - \frac{{31}} {{32}} \cr} $ |