toepassen van de rekenregels

 $\Large \frac{{2x + 1}} {{x^2 - 2}} = 0$ $\frac{A} {B} = 0 \to A = 0$ $2x + 1 = 0$ $\Large \frac{{2x - 1}} {{x^2 - 2}} = x$ $\frac{A} {B} = C \to A = BC$ $2x - 1 = x\left( {x^2 - 2} \right)$ $\Large \frac{{2x - 1}} {{x^2 - 2}} = \frac{{2x - 1}} {{x^3 }}$ $\frac{A} {B} = \frac{A} {C} \to A = 0 \vee B = C$ $2x - 1 = 0 \vee x^2 - 2 = x^3$

 $\Large \frac{{2x - 1}} {{x^2 - 2}} = \frac{3} {{x^3 }}$ $\frac{A} {B} = \frac{C} {D} \to AD = BC$ $x^3 \left( {2x - 1} \right) = 3\left( {x^2 - 2} \right)$ $\Large \frac{{2x - 1}} {{x^2 - 2}} = \frac{3} {{x^2 - 2}}$ $\frac{A} {B} = \frac{C} {B} \to A = C$ $2x - 1 = 3$