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$$ \eqalign{ & z^2 + z^2 = \left( {6\sqrt 3 } \right)^2 \cr & 2z^2 = 108 \cr & z^2 = 54 \cr & z = \pm 3\sqrt 6 \cr} $$ |
$$ \eqalign{ & z^2 + z^2 = \left( {10\sqrt 5 } \right)^2 \cr & 2z^2 = 500 \cr & z^2 = 250 \cr & z = \pm 5\sqrt {10} \cr} $$ |
$$ \eqalign{ & z^2 + z^2 = \left( {14\sqrt 7 } \right)^2 \cr & 2z^2 = ... \cr & z^2 = ... \cr & z = \pm 7\sqrt {14} \cr} $$ |
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$$ \frac{1} {{\sqrt 3 }} = \frac{{AB}} {{6\sqrt 2 }} \Rightarrow AB = 2\sqrt 6 $$ |
$$ \frac{1} {{\sqrt 3 }} = \frac{{AB}} {{15\sqrt 5 }} \Rightarrow AB = 5\sqrt {15} $$ |
$$ \frac{1} {{\sqrt 3 }} = \frac{{AB}} {{39\sqrt {13} }} \Rightarrow AB = 13\sqrt {39} $$ |
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$\sqrt{3}+\sqrt{2}=\sqrt{5}$
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$\sqrt{3}\times\sqrt{2}=\sqrt{6}$
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$2\times\sqrt{3}=\sqrt{12}$
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$\sqrt{8}+\sqrt{18}=\sqrt{50}$
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$\sqrt { - 7} = - \sqrt 7$
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$\sqrt{7}\times-\sqrt{7}=7$
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$ \frac{1}{2}\sqrt{2}=\sqrt{\frac{1}{2}}$
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$\sqrt{12}+\sqrt{27}=\sqrt{75}$
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